16x^2-9/4x+3=-6

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Solution for 16x^2-9/4x+3=-6 equation: 


x in (-oo:+oo)

16*x^2-((9/4)*x)+3 = -6 // + 6

16*x^2-((9/4)*x)+3+6 = 0

16*x^2+(-9/4)*x+3+6 = 0

16*x^2-9/4*x+9 = 0

DELTA = (-9/4)^2-(4*9*16)

DELTA = -9135/16

DELTA < 0

x belongs to the empty set

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